Origins of the universe
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From: mpc755 on 28 Jun 2010 20:51 On Jun 28, 8:29�pm, aganunitsi <ssyke...(a)mindspring.com> wrote: > On Jun 28, 5:07 pm, mpc755 <mpc...(a)gmail.com> wrote: > <aethereal snip> > > > Correct. But each C-60 molecule enters and exits a single slit. The > > moving C-60 molecule has an associated aether displacement wave. It is > > the aether displacement wave which enters and exits multiples slits, > > creating interference upon exiting the slits which alters the > > direction the C-60 molecule, which entered and exited a single slit, > > travels. Detecting the C-60 molecule causes decoherence of the > > associated aether displacement wave (i.e. turns the wave into chop) > > and there is no interference. > > You're not stating the entirety of observations made in a double slit > experiment. Only one detector pointed at one of the two slits is > required. Non-detection of a particle occurs 50% of the time (meaning > the particle must have gone through the other slit), but we do not > observe a 50% particle like strike pattern mixed with a 50% wave like > interference strike pattern on the final detector. > An experiment with one detector is more evidence the C-60 molecule enters and exits a single slit. Either the molecule, 100% of it, is detected exiting a single slit or no molecule, 0% of it, is detected exiting a single slit. > If there is a separate aether displacement wave that always goes > through both slits, this wouldn't be the observation. > Of course it would be. The C-60 molecule always goes through a single slit. > <superpositional snip>> Explain how a C-60 molecule enters, travels through and exits multiple > > slits simultaneously without requiring energy releasing energy or > > having a change in momentum. > > <snip> > > It's called superposition. I suggest you read up on quantum > decoherence:http://en.wikipedia.org/wiki/Quantum_decoherence It's called the absurd nonsense of the Copenhagen interpretation of QM. If you want to understand how a particle has an associated wave and the particle travels a single path, you should read: http://www.ensmp.fr/aflb/AFLB-classiques/aflb124p001.pdf "I called this relation, which determines the particle�s motion in the wave, �the guidance formula�. It may easily be generalized to the case of an external field acting on the particle." The external field acting on the particle is the aether. http://nobelprize.org/nobel_prizes/physics/laureates/1929/broglie-lecture.pdf
From: mpc755 on 28 Jun 2010 21:33 On Jun 28, 8:29�pm, aganunitsi <ssyke...(a)mindspring.com> wrote: > On Jun 28, 5:07 pm, mpc755 <mpc...(a)gmail.com> wrote: > <aethereal snip> > > > Correct. But each C-60 molecule enters and exits a single slit. The > > moving C-60 molecule has an associated aether displacement wave. It is > > the aether displacement wave which enters and exits multiples slits, > > creating interference upon exiting the slits which alters the > > direction the C-60 molecule, which entered and exited a single slit, > > travels. Detecting the C-60 molecule causes decoherence of the > > associated aether displacement wave (i.e. turns the wave into chop) > > and there is no interference. > > You're not stating the entirety of observations made in a double slit > experiment. Only one detector pointed at one of the two slits is > required. Non-detection of a particle occurs 50% of the time (meaning > the particle must have gone through the other slit), but we do not > observe a 50% particle like strike pattern mixed with a 50% wave like > interference strike pattern on the final detector. > > If there is a separate aether displacement wave that always goes > through both slits, this wouldn't be the observation. > So, you're suggesting detectors at the exits to the slit, there to detected the C-60 molecule, should detected the aether displacement wave, but if there are no detectors at the exits at all, then the C-60 molecule magically exits both slits and interferes with itself. Is this correct? Explain the following. A C-60 molecule is in the slit(s). Detectors are placed at the exits. The C-60 molecule is always detected exiting a single slit. A C-60 molecule is in the slit(s). Detectors are placed and removed from the exits. Repeat and the C-60 molecules create an interference pattern. How is this possible? Why is the C-60 molecule always detected exiting a single slit? Because the C-60 molecule always enters and exits a single slit, duh! Here is an experiment. Place a detector at one of the exits of a double slit experiment. Fire a particle. Have the particle be detected and not exit the slit. Fire another particle across the front of the open slit at the time the particle would exit the slit if the particle had entered that slit. The aether displacement wave should alter the direction the particle fired in front of the slits travels. The Copenhagen interpretation of QM can not answer this experimental evidence because all there is is the particle and once it is detected, that's it. Anything exiting the other slit would cause the Copenhagen interpretation of QM to fail conservation of momentum. > <superpositional snip>> Explain how a C-60 molecule enters, travels through and exits multiple > > slits simultaneously without requiring energy releasing energy or > > having a change in momentum. > > <snip> > > It's called superposition. I suggest you read up on quantum > decoherence:http://en.wikipedia.org/wiki/Quantum_decoherence
From: BURT on 28 Jun 2010 23:07 On Jun 28, 5:09�pm, mpc755 <mpc...(a)gmail.com> wrote: > On Jun 28, 8:59 am, Nick Keighley <nick_keighley_nos...(a)hotmail.com> > wrote: > > > > > > > On 27 June, 04:55, mpc755 <mpc...(a)gmail.com> wrote: > > > > On Jun 26, 11:33 pm, Boikat <boi...(a)bellsouth.net> wrote: > > > > On Jun 26, 10:27 pm, mpc755 <mpc...(a)gmail.com> wrote: > > > > > > On Jun 26, 4:15 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > > > > "I want to know how God created the universe. I want to know his > > > > > > thoughts. The rest are just details." Albert EInstein > > > > > > > Hypersphere cosmology was the beginning with energy created in its > > > > > > surface of space. First there was inflation that stopped gravity from > > > > > > bringing it all back together. Einstein's universe is closed finite > > > > > > yet unbounded hypersphere cosmology. > > > > > > > Mitch Raemsch > > > > > > The universe is, or the local universe is in, a jet stream. > > > > > > The following is an image of a jet stream: > > > > > >http://aether.lbl.gov/image_all.html > > > > > No, that's a schematic representation of size of the Universe through > > > > time. > > > > It's not the Big Bang. It's the Big Ongoing. > > > > Aether and matter are different states of the same material. > > > The material is maether. > > > Maether has mass. > > > > Maether is continually emitted into the jet stream the universe is, or > > > the local universe exists in. > > > > In the following image, '1st Stars' is where the pressure is great > > > enough to cause the maether to be compressed into matter. > > > >http://aether.lbl.gov/image_all.html > > > > The following image of the Rindler Horizon is also an image of the jet > > > stream the universe is, or the local universe exists in: > > > >http://en.wikipedia.org/wiki/Rindler_coordinates#Geodesics-Hidequoted text - > > > did someone not check the child gate was properly latched when they > > left sci.physics? > > How is matter formed? > > Are you going to say from energy? From radiation? > > Mass is conserved. > > Aether and matter are different states of the same material. > Aether is uncompressed maether and matter is compressed maether. > > In the following image, '1st Stars' is where the pressure is great > enough to cause the maether to be compressed into matter. > > http://aether.lbl.gov/image_all.html > > A=Mc^2, where A is aether and M is matter.- Hide quoted text - > > - Show quoted text - There is no molecule wave. Mitch Raemsch
From: aganunitsi on 28 Jun 2010 23:13 On Jun 28, 6:33�pm, mpc755 <mpc...(a)gmail.com> wrote: <particle snip> > So, you're suggesting detectors at the exits to the slit, there to > detected the C-60 molecule, should detected the aether displacement > wave, but if there are no detectors at the exits at all, then the C-60 > molecule magically exits both slits and interferes with itself. > > Is this correct? No definitely not correct. No aether displacement wave should be detected because such a thing does not exist. You can say "magically" if you like, but the correct terminology is "scientifically". An undetectable aether displacement wave that goes through both slits sounds magical to me. Especially when a theory of such a thing is incapable of generating any observable scientific results. The Copenhagen Interpretation, on the other hand, has lead to observable results. How does your unobservable aether wave explain this?: http://www.nature.com/news/2010/100317/full/news.2010.130.html A modified double slit experiment has even been used to show superposition in time as well as space: http://physicsworld.com/cws/article/news/21623 If you're going to propose a grand theory that rocks the boat, you really should keep up with the boat. You're still sitting at the dock and the boat set sail decades ago. > Explain the following. > > A C-60 molecule is in the slit(s). Detectors are placed at the exits. > The C-60 molecule is always detected exiting a single slit. A C-60 > molecule is in the slit(s). Detectors are placed and removed from the > exits. Repeat and the C-60 molecules create an interference pattern. > > How is this possible? > > Why is the C-60 molecule always detected exiting a single slit? > > Because the C-60 molecule always enters and exits a single slit, duh! <wave snip> When exposed to a sufficiently large system of decoherence, such as is the detector at a slit, the wave function collapses and the C-60 molecule dephases from a coherent wave function into a decoherent particle. With no detector at either slit, the wave function does not collapse until it strikes the detector screen (another macroscopic system of decoherence). The difference is observed in the pattern created on the screen. With no detector at either slit, a wave interference pattern requiring a wave passing through both slits simultaneously is observed on the screen, even when only one molecule (or subatomic particle) is fired at a time. Self interference is observed. What observable results does your aether wave theory predict which are conclusively different from the observable results already used to create technological achievements by those who follow the Copenhagen Interpretation? In other words, how is your aether wave theory falsifiable?
From: mpc755 on 28 Jun 2010 23:50
On Jun 28, 11:13�pm, aganunitsi <ssyke...(a)mindspring.com> wrote: > On Jun 28, 6:33�pm, mpc755 <mpc...(a)gmail.com> wrote: > <particle snip> > > > So, you're suggesting detectors at the exits to the slit, there to > > detected the C-60 molecule, should detected the aether displacement > > wave, but if there are no detectors at the exits at all, then the C-60 > > molecule magically exits both slits and interferes with itself. > > > Is this correct? > > No definitely not correct. No aether displacement wave should be > detected because such a thing does not exist. You can say "magically" > if you like, but the correct terminology is "scientifically". An > undetectable aether displacement wave that goes through both slits > sounds magical to me. Especially when a theory of such a thing is > incapable of generating any observable scientific results. The observable result is the interference pattern in every double slit experiment ever performed. If you perform an experiment and place detectors at the exits to the slits and you always detect the particle exiting a single slit then do you know what that is? It is evidence the particle always enters and exits a single slit. > The > Copenhagen Interpretation, on the other hand, has lead to observable > results. > > How does your unobservable aether wave explain this?:http://www.nature.com/news/2010/100317/full/news.2010.130.html > They are detecting the associated aether wave. > A modified double slit experiment has even been used to show > superposition in time as well as space:http://physicsworld.com/cws/article/news/21623 > Detecting, or determining, which-way destroys the cohesion of the associated aether wave and there is no interference. > If you're going to propose a grand theory that rocks the boat, you > really should keep up with the boat. You're still sitting at the dock > and the boat set sail decades ago. > > > Explain the following. > > > A C-60 molecule is in the slit(s). Detectors are placed at the exits. > > The C-60 molecule is always detected exiting a single slit. A C-60 > > molecule is in the slit(s). Detectors are placed and removed from the > > exits. Repeat and the C-60 molecules create an interference pattern. > > > How is this possible? > > > Why is the C-60 molecule always detected exiting a single slit? > > > Because the C-60 molecule always enters and exits a single slit, duh! > > <wave snip> > > When exposed to a sufficiently large system of decoherence, such as is > the detector at a slit, the wave function collapses and the C-60 > molecule dephases from a coherent wave function into a decoherent > particle. The particle travels a single path. Detecting the particle causes decoherence of the associated aether displacement wave (i.e. turns the aether wave into chop) and there is no interference. > With no detector at either slit, the wave function does not > collapse until it strikes the detector screen (another macroscopic > system of decoherence). With no detector at either slit, the coherence of the associated aether displacement wave is maintained and creates interference which alters the direction the particle travels. > The difference is observed in the pattern > created on the screen. With no detector at either slit, a wave > interference pattern requiring a wave passing through both slits > simultaneously is observed on the screen, Correct. The aether wave passing through both slits simultaneously causes interference upon exiting the slits which alters the direction the particle travels. > even when only one molecule (or subatomic particle) is fired at a time. Correct. Because the moving molecule (or moving subatomic particle), which is fired one at a time, has an associated aether wave. > Self interference is observed. Incorrect. The aether wave exits the slits and creates interference which alters the direction the particle travels. A moving particle has an associated aether wave. > > What observable results does your aether wave theory predict which are > conclusively different from the observable results already used to > create technological achievements by those who follow the Copenhagen > Interpretation? In other words, how is your aether wave theory > falsifiable? I already mentioned placing a detector at the exit to one of the slits and firing a second particle across the front of the open slit. The aether wave exiting the open slit will alter the direction the second particle travels. The following is an explanation of what occurs in nature in a 'delayed choice quantum eraser' experiment. Following the explanation are two experiments which will provide evidence of Aether Displacement. In the image on the right here: http://en.wikipedia.org/wiki/Delayed_choice_quantum_eraser#The_experiment When the downgraded photon pair are created, in order for there to be conservation of momentum, the original photons momentum is maintained. This means the downgraded photon pair have opposite angular momentums. We will describe one of the photons as being the 'up' photon and the other photon as being the 'down' photon. One of the downgraded photons travels either the red or blue path towards D0 and the other photon travels either the red or blue path towards the prism. There are physical waves in the aether propagating both the red and blue paths. The aether waves propagating towards D0 interact with the lens and create interference prior to reaching D0. The aether waves create interference which alters the direction the photon travels prior to reaching D0. There are actually two interference patterns being created at D0. One associated with the 'up' photons when they arrive at D0 and the other interference pattern associated with the 'down' photons when they arrive at D0. Both 'up' and 'down' photons are reflected by BSa and arrive at D3. Since there is a single path towards D3 there is nothing for the wave in the aether to interfere with and there is no interference pattern and since it is not determined if it is an 'up' or 'down' photon being detected at D3 there is no way to distinguish between the photons arriving at D0 which interference pattern each photon belongs to. The same for photons reflected by BSb and arrive at D4. Photons which pass through BSa and are reflected by BSc and arrive at D1 are either 'up' or 'down' photons but not both. If 'up' photons arrive at D1 then 'down' photons arrive at D2. The opposite occurs for photons which pass through BSb. Photons which pass through BSa and pass through BSb and arrive at D1 are all either 'up' or 'down' photons. If all 'up' photons arrive at D1 then all 'down' photons arrive at D2. Since the physical waves in the aether traveling both the red and blue paths are combined prior to D1 and D2 the aether waves create interference which alters the direction the photon travels. Since all 'up' photons arrive at one of the detectors and all 'down' photons arrive at the other an interference pattern is created which reflects back to the interference both sets of photons are creating at D0. Figures 3 and 4 here: http://arxiv.org/PS_cache/quant-ph/pdf/9903/9903047v1.pdf Show the interference pattern of the 'up' and 'down' photons. If you were to combine the two images and add the peaks together and add the valleys together you would have the interference pattern of the original photon. This is evidence the downgraded photon pair maintain the original photons momentum and have opposite angular momentums. Nothing is erased. There is no delayed choice. Physical waves in the aether are traveling both the red and blue paths and when the paths are combined the waves create interference which alters the direction the photon 'particle' travels. Experiments which will provide evidence of Aether Displacement: Experiment #1: Instead of having a single beam splitter BSc have two beam splitters BSca and BScb. Have the photons reflected by mirror Ma interact with BSca and have the photons reflected by mirror Mb interact with BScb. Do not combine the red and blue paths. Have additional detectors D1a, D2a, D1b, and D2b. Have the photons reflected by and propagate through BSca be detected at D1a and D2a. Have the photons reflected by and propagate through BScb be detected at D1b and D2b. If you compare the photons detected at D1a and D1b with the photons detected at D0, the corresponding photons detected at D0 will form an interference pattern. If you compare the photons detected at D2a and D2b with the photons detected at D0, the corresponding photons detected at D0 will form an interference pattern. What is occurring is all 'up' photons are being detected at one pair of detectors, for example D1a and D1b, and all 'down' photons are being detected at the other pair of detectors, for example D2a and D2b. Interference patterns do not even need to be created in order to 'go back' and determine the interference patterns created at D0. Experiment #2: Alter the experiment. When the downgraded photon pair are created, have each photon interact with its own double slit apparatus. Have detectors at one of the exits for each double slit apparatus. When a photon is detected at one of the exits, in AD, the photon's aether wave still exists and is propagating along the path exiting the other slit. When a photon is not detected at one of the exits, the photon 'particle' along with its associated aether wave exits the other slit. Combine the path the aether wave the detected photon is propagating along with the path of the other photon and its associated aether wave. An interference pattern will still be created. This shows the aether wave of a detected photon still exists and is able to create interference with the aether wave of another photon, altering the direction the photon 'particle' travels. |