From: Jon Slaughter on
Whats the formula?

I = 1/2*F*Q*V?

Trying to figure out if I can drive

http://www.fairchildsemi.com/pf/FD/FDD8424H.html

with a uC directly? (I think it can supply up to 20mA or so)

V = 12V if I use pullup and 5V if not.

Thanks,
Jon


From: John Larkin on
On Thu, 10 Apr 2008 17:33:44 -0600, "Jon Slaughter"
<Jon_Slaughter(a)Hotmail.com> wrote:

>Whats the formula?
>
>I = 1/2*F*Q*V?
>
>Trying to figure out if I can drive
>
>http://www.fairchildsemi.com/pf/FD/FDD8424H.html
>
>with a uC directly? (I think it can supply up to 20mA or so)
>
>V = 12V if I use pullup and 5V if not.
>
>Thanks,
>Jon
>

How fast (rise/fall) do you need to switch?

John

From: bill.sloman on
On 11 apr, 01:33, "Jon Slaughter" <Jon_Slaugh...(a)Hotmail.com> wrote:
> Whats the formula?
>
> I = 1/2*F*Q*V?
>
> Trying to figure out if I can drive
>
> http://www.fairchildsemi.com/pf/FD/FDD8424H.html
>
> with a uC directly? (I think it can supply up to 20mA or so)
>
> V = 12V if I use pullup and 5V if not.

Check out the data sheet. Figure 7 shows the typical gate charge
required to get the gate voltage up to a level where the part is
turned on - something like 10nC. The worst case total gate charge
listed earlier in the data sheet is 24uC.

20mA s going to take 1.2usec to deliver that 24uC of charge - this is
slow switching by MOSFET standards, and you won't want to switch that
slowly very often, because if you do there is a real risk that the
switch will overheat.

--
Bill Sloman, Nijmegen
From: Fred Bloggs on


bill.sloman(a)ieee.org wrote:
> On 11 apr, 01:33, "Jon Slaughter" <Jon_Slaugh...(a)Hotmail.com> wrote:
>
>>Whats the formula?
>>
>>I = 1/2*F*Q*V?
>>
>>Trying to figure out if I can drive
>>
>>http://www.fairchildsemi.com/pf/FD/FDD8424H.html
>>
>>with a uC directly? (I think it can supply up to 20mA or so)
>>
>>V = 12V if I use pullup and 5V if not.
>
>
> Check out the data sheet. Figure 7 shows the typical gate charge
> required to get the gate voltage up to a level where the part is
> turned on - something like 10nC. The worst case total gate charge
> listed earlier in the data sheet is 24uC.
>
> 20mA s going to take 1.2usec to deliver that 24uC of charge - this is
> slow switching by MOSFET standards, and you won't want to switch that
> slowly very often, because if you do there is a real risk that the
> switch will overheat.
>
> --
> Bill Sloman, Nijmegen

That thing looks like a cross conduction hazard and half at that
switching speed, both FETs come on at less than 2V from their source
rails, wonder if he's tying the gates together, definitely would want to
switch as fast as possible then...

From: Jon Slaughter on

<bill.sloman(a)ieee.org> wrote in message
news:20e9d847-ea21-4aa1-bb24-4a2848d7a57a(a)q24g2000prf.googlegroups.com...
> On 11 apr, 01:33, "Jon Slaughter" <Jon_Slaugh...(a)Hotmail.com> wrote:
>> Whats the formula?
>>
>> I = 1/2*F*Q*V?
>>
>> Trying to figure out if I can drive
>>
>> http://www.fairchildsemi.com/pf/FD/FDD8424H.html
>>
>> with a uC directly? (I think it can supply up to 20mA or so)
>>
>> V = 12V if I use pullup and 5V if not.
>
> Check out the data sheet. Figure 7 shows the typical gate charge
> required to get the gate voltage up to a level where the part is
> turned on - something like 10nC. The worst case total gate charge
> listed earlier in the data sheet is 24uC.
>
> 20mA s going to take 1.2usec to deliver that 24uC of charge - this is
> slow switching by MOSFET standards, and you won't want to switch that
> slowly very often, because if you do there is a real risk that the
> switch will overheat.
>

Why is slower going to going to cause it to heat up? Its less current so
less heat (same amount of charge). In fact it probably would be better
because its spread out over time. (like, say, charging a battery at 1A for 1
year compared to 365A in one day. Same amount of charge but totally diffrent
results)

My switching is at most 100khz(its for motor control so anything about 20khz
should be ok but I'm going for about 50khz). I figure I need about 5 to 10
times this but really it shouldn't be that important(don't need it to be
exact).

Really though, Can you explain to me why a slower switching speed will cause
it to heat up more? It contradict's everything I know about transister
switches and switching speed.


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