Win Hill: Inverse Marx Generator ??
in [Design]
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From: krw on 11 Jul 2010 21:02 On Sun, 11 Jul 2010 17:54:24 -0700, AM <thisthatandtheother(a)beherenow.org> wrote: >On Sun, 11 Jul 2010 17:44:07 -0700, "Artemus" <bogus(a)invalid.org> wrote: > >> (plus other energy which I'll >>ignore for this example). > > You are also easy to ignore. Particluarly when he's right, AlwaysWrong.
From: krw on 11 Jul 2010 21:02 On Sun, 11 Jul 2010 17:44:07 -0700, "Artemus" <bogus(a)invalid.org> wrote: > >"AM" <thisthatandtheother(a)beherenow.org> wrote in message >news:p6ok36919v7q6d8cbfhmu8vr4lnvhu18do(a)4ax.com... >> On Sun, 11 Jul 2010 17:23:15 -0700, "Artemus" <bogus(a)invalid.org> wrote: >> >> > >> >"AM" <thisthatandtheother(a)beherenow.org> wrote in message >> >news:d6mk36h052rlhlhnjvsjm3echd2p2n93sn(a)4ax.com... >> >> On Sun, 11 Jul 2010 16:44:12 -0700, "Artemus" <bogus(a)invalid.org> wrote: >> >> >> >> > >> >> >"AM" <thisthatandtheother(a)beherenow.org> wrote in message >> >> >news:k0kk369ft5vabhv9btnr1ffatpej9p369o(a)4ax.com... >> >> >> On Sun, 11 Jul 2010 16:03:27 -0700, "Artemus" <bogus(a)invalid.org> wrote: >> >> >> >> >> >> > And, yet there is NO energy >> >> >> >flowing into nor out of the box. >> >> >> >> >> >> Bullshit. If the light is on, it is emitting energy. >> >> >> >> >> >> Period. >> >> > >> >> >Did you miss the part about the box, and the flashlight it contains, >> >> >being a closed and isolated system? >> >> >Art >> >> > >> >> >> >> If the light is on, it is adding heat to the box. >> > >> >You really can't take the ball and run it to the goal line can you? >> >Art >> > >> > >> I can see that you carry a lot of stored, latent retardation. >> >> Go to another group. You deserve to be closed and isolated. > >I really doubt that you can see anything. However, I'll try to enlighten >you on the off chance you may want to learn something. >The box is a closed system. It contains some latent heat energy >AND chemical energy in the battery (plus other energy which I'll >ignore for this example). The battery's chemical energy is converted >to electrical energy which is eventually converted to heat which raises >the temperature of the box. There is no need for any external input of >energy to raise the temperature of the box. Get it now? You added energy to the system when you put the flashlight (batteries) into the box.
From: John Larkin on 11 Jul 2010 21:30 On Sun, 11 Jul 2010 17:57:08 -0700, AM <thisthatandtheother(a)beherenow.org> wrote: >On Sun, 11 Jul 2010 17:44:07 -0700, "Artemus" <bogus(a)invalid.org> wrote: > >> There is no need for any external input of >>energy to raise the temperature of the box. Get it now? > > There was energy used to charge the battery. That happened outside the >box. > > Performing the same set-up with a battery with nothing to offer will >not follow your claim. > > Since you did not specify that the battery for the lamp be charged, you >failed to properly define the circumstance. I specified "lighted flashlight." John
From: Artemus on 11 Jul 2010 21:52 "AM" <thisthatandtheother(a)beherenow.org> wrote in message news:lupk36ha175fjscdvjl2duqvnpqsl0t50b(a)4ax.com... > On Sun, 11 Jul 2010 17:44:07 -0700, "Artemus" <bogus(a)invalid.org> wrote: > > > There is no need for any external input of > >energy to raise the temperature of the box. Get it now? > > There was energy used to charge the battery. That happened outside the > box. > > Performing the same set-up with a battery with nothing to offer will > not follow your claim. > > Since you did not specify that the battery for the lamp be charged, you > failed to properly define the circumstance. > > Bogus(a)invalid fits you well. Like the hypothetical box your mind is a closed system as well. Into the bozo bin with you. Art
From: kevin93 on 11 Jul 2010 22:34
On Jul 11, 2:27 pm, John Larkin <jjlar...(a)highNOTlandTHIStechnologyPART.com> wrote: > On Sun, 11 Jul 2010 15:47:02 -0500, John Fields .... > It's conserved in some circuits, such as caps and resistances in > series with no shunt paths, like Jim's ancient riddle (or is it > ancient Jim's riddle?) It's not conserved in other cases, like my > inductive energy transfer example, or when you just plain discharge a > cap through a resistor. .... > > John Are you meaning the scenario with an inductor connecting two capacitors? In that case the total charge on the two capacitors will be constant - it has to be. The integral of the current out of one cap is the same as the integral into the other. The only way for it to be different is if there is a connection to the other side of the capacitors. If you add a switch (or just a diode) you can stop the process when maximum energy has been transferred to the second capacitor - this has been used for many decades in pulse RADAR systems to charge the pulse forming network. I agree with you that it is not at all accurate to just quote the "Charge is conserved mantra" but in some situations it will be true. kevin |