GETTING RID OF EINSTEIN RELATIVITY
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From: George Dishman on 14 Oct 2007 10:30 "Clueless Henri Wilson" <HW@....> wrote in message news:kjg3h35ok4vf1n6ik43dl2ga79s1q0o327(a)4ax.com... > On Sat, 13 Oct 2007 17:27:08 +0100, "George Dishman" > <george(a)briar.demon.co.uk> wrote: >> >>When you realise Henry counts 11.2 over 424.4 degrees >>and 7.8 waves over 205.6 degrees, you might understand >>what he is trying to do. With a bit more help from me, >>you might even understand why his approach is never >>going to work. > > It DOES work....and it produces the right answer.. It gives you the answer you WANT. It isn't the CORRECT answer, you need to learn how an interferometer works. Start with the applet and instructions in my other post and I'll try to educate you when you immediately leap to the wrong conclusion. George
From: George Dishman on 14 Oct 2007 10:35 "Dr. Henri Wilson" <HW@....> wrote in message news:gff2h3t1b7usrumct7fq6ae36bdql9fbsl(a)4ax.com... > On Fri, 12 Oct 2007 22:21:51 +0100, "George Dishman" > <george(a)briar.demon.co.uk> wrote: >>"Androcles" <Engineer(a)hogwarts.physics> wrote in message >>news:u3OPi.322498$xp6.195098(a)fe3.news.blueyonder.co.uk... > >> >> http://www.androcles01.pwp.blueyonder.co.uk/Sagnac/MechSagnac.gif >> >>The teeth on the wheels are equally spaced. >> >>> That's two that idiots that can't count. I wonder how many more >>> there are... 60 teeth on each wheel, 6 degrees apart, he can't count and he even drew it. >>No, you're own your own this time, even Henry got it right. >> >>> : > lambda_blue =(2pi+alpha)R/9.5 >>> : > lambda_red = (2pi - alpha)R/9.5 >>> : > Changing the NUMBER of waves is Wilson tick fairy work. >> >>The number 9.5 is from the source to the detector so >>it is (2*pi*R)/9.5 for both waves. > > The number from the emision point is 13 blue, 6 red. But the angles between the emission and detection points aren't 2 pi radians in ewither direction. Why are you arguing Henry, I am trying explain to Andy why _you_ are _right_? >> http://www.georgedishman.f2s.com/Henri/SameWavelength.png >> >>Or you can count from the yellow dot to the >>green dot: >> >> http://www.georgedishman.f2s.com/Henri/NumberOfWaves.png >> >> lambda_blue =(2pi + alpha)R / 11.2 >> lambda_red = (2pi - alpha)R / 7.8 >> >>You get the same wavelength by either method. Get it yet? "You get the same wavelength by either method." I am saying your claim is _correct_ so stop and _think_ before disagreeing! George
From: Dr. Henri Wilson on 14 Oct 2007 18:04 On Sun, 14 Oct 2007 00:12:33 GMT, "Androcles" <Engineer(a)hogwarts.physics> wrote: > >"Dr. Henri Wilson" <HW@....> wrote in message >news:gff2h3t1b7usrumct7fq6ae36bdql9fbsl(a)4ax.com... >: On Fri, 12 Oct 2007 22:21:51 +0100, "George Dishman" ><george(a)briar.demon.co.uk> >: wrote: >: >: >The number 9.5 is from the source to the detector so >: >it is (2*pi*R)/9.5 for both waves. >: >: The number from the emision point is 13 blue, 6 red. > >You are counting the same 3.5 of them twice: > http://www.androcles01.pwp.blueyonder.co.uk/Sagnac/z4.gif >Thirteen "wavelengths" (distance a photon has to move in one of its cycles) >are needed to catch up to the moving source in one revolution when moving >counterclockwise, eleven are needed in the clockwise direction. Yet at any >given instant there are exactly twelve in the circumference. >The tick fairy changed 1 of them in my model, 3.5 of them in Jeery's model. >You pair of idiots cannot count and are oh-so-easy to fool. > http://www.androcles01.pwp.blueyonder.co.uk/tickfairy.gif >How many teeth on each wheel? The path lengths are 2piR+/-vt. The difference in number of wavelengths is 4Aw/cLambda. That is the correct answer,....backed by experiment. Nobody cares what you and George think. Nature just works this way. Henri Wilson. ASTC,BSc,DSc(T) www.users.bigpond.com/hewn/index.htm
From: Dr. Henri Wilson on 14 Oct 2007 18:06 On Sun, 14 Oct 2007 00:12:34 GMT, "Androcles" <Engineer(a)hogwarts.physics> wrote: > >"Dr. Henri Wilson" <HW@....> wrote in message >news:50g2h39b2gg6pv4e1sm847cgeue23ubscq(a)4ax.com... >: On Fri, 12 Oct 2007 15:40:18 +0100, "George Dishman" ><george(a)briar.demon.co.uk> >: wrote: >: >: > >: >"Dr. Henri Wilson" <HW@....> wrote in message >: >news:e7gmg3hgn3dqejmkarjnb1l83m5hp2q5rh(a)4ax.com... >: >> On Tue, 09 Oct 2007 00:13:59 -0700, George Dishman >: >> <george(a)briar.demon.co.uk> >: >> wrote: >: >: >>>Look at the simulation once it has stopped. Count >: >>>the number of waves, it is 9.5 in both directions. >: >> >: >> The number of waves between the static emission point and the end point >is >: >> certainly not the same in both rays. >: > >: >The above number is from source to detector at >: >any instant. >: >: Using that figure leads to your mistake. >: Do you think the waves emitted at the yellow line disappear somehow? >: >: There are about 13 waves in the blue and 6 in the red. > >You pair of morons cannot count. > http://www.androcles01.pwp.blueyonder.co.uk/tickfairy.gif >How many teeth in each wheel? The path lengths are 2piR+/-vt. The difference in number of wavelengths is 4Aw/cLambda. That is the correct answer,....backed by experiment. Nobody cares what you and George think. Nature just works this way. Henri Wilson. ASTC,BSc,DSc(T) www.users.bigpond.com/hewn/index.htm
From: Dr. Henri Wilson on 14 Oct 2007 18:07
On Sun, 14 Oct 2007 00:12:34 GMT, "Androcles" <Engineer(a)hogwarts.physics> wrote: > >"Dr. Henri Wilson" <HW@....> wrote in message >news:b3i2h3d67j45p53mbc04b3n0up91ud49nl(a)4ax.com... >: On Fri, 12 Oct 2007 15:24:08 +0100, "George Dishman" ><george(a)briar.demon.co.uk> >: wrote: >: >: > >: >"George Dishman" <george(a)briar.demon.co.uk> wrote in message >: >news:1192027957.218767.273550(a)57g2000hsv.googlegroups.com... >: >> On 10 Oct, 09:13, "Androcles" <Engin...(a)hogwarts.physics> wrote: >: > >: >... >: >: >> >: >> lambda = circumference / 9.5 >: >> >: >> in both directions. Hit the pause button when >: >> the two waves coincide and you can see they >: >> are the same as they should be. >: > >: >Here is a screenshot of the applet proving the >: >point: >: > >: > http://www.georgedishman.f2s.com/Henri/SameWavelength.png >: >: George, the emission point is the yellow line. > >You pair of imbeciles cannot count. > http://www.androcles01.pwp.blueyonder.co.uk/tickfairy.gif >How many teeth in each wheel? You have to count from the emission point to the detector...but Jerry's program doesn't stop where it should so it's useless. >/index.htm > Henri Wilson. ASTC,BSc,DSc(T) www.users.bigpond.com/hewn/index.htm |