GETTING RID OF EINSTEIN RELATIVITY
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From: Dr. Henri Wilson on 17 Oct 2007 17:34 On Wed, 17 Oct 2007 00:47:49 GMT, "Androcles" <Engineer(a)hogwarts.physics> wrote: > >"Dr. Henri Wilson" <HW@....> wrote in message >news:s6fah3hr1l27bkm48mtodblbhl79afkk5u(a)4ax.com... >: On Mon, 15 Oct 2007 22:41:48 GMT, "Androcles" <Engineer(a)hogwarts.physics> >: wrote: >: >: > >: >"Dr. Henri Wilson" <HW@....> wrote in message >: >news:u8p7h3l41okcp8vsnitaikbp10e04fipan(a)4ax.com... >: >: >: >>>You get the same wavelength by either method. >: >: > >: >: >Get it yet? >: >: > >: >: >"You get the same wavelength by either method." >: >: > >: >: >I am saying your claim is _correct_ so stop and >: >: >_think_ before disagreeing! >: >: >: >: I'm basicaly disagreeing with him. >: > >: > >: >That's good, Wilson, I want it on record that you disagreed with me. >: > >: >"There are about 13 waves in the blue and 6 in the red." --Wilson, 12 Oct >: >2007. >: >"the number of waves between the source and detector is >: >the same in both paths and constant." -- Wilson, 15 Oct 2007. >: >: Both above statements are correct. >: It is no fault of mine if you cannot get into your head that the >'stationary >: emission point' is NOT the same thing as the 'moving source'. > > >It is no fault of mine if you cannot count. > http://www.androcles01.pwp.blueyonder.co.uk/tickfairy.gif >How many teeth on each wheel have I drawn? > Is it >A) 20 >B) 21 >C) 22 >D) 23 >E) 24 >F) 25 >G) 26 >H) 27 >I) 28 >J) 29 >K) 30 >L) Other ......................... (specify) ...now count the number of teeth between the common EMISSION POINT and the detector when the rays reunite. >: >"That's the kind of argument I'd expect from a desperate >: >person....completely out of ideas... ahahahaha!" -- Wilson. >: > >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA >: >AHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA! >: >: get off the whisky.... > >"That's the kind of argument I'd expect from a desperate >person....completely out of ideas... ahahahaha!" -- Wilson. > Henri Wilson. ASTC,BSc,DSc(T) www.users.bigpond.com/hewn/index.htm
From: Dr. Henri Wilson on 17 Oct 2007 17:48 On Wed, 17 Oct 2007 00:37:17 -0700, George Dishman <george(a)briar.demon.co.uk> wrote: >On 16 Oct, 23:45, HW@....(Clueless Henri Wilson) wrote: >> On Tue, 16 Oct 2007 00:50:38 -0700, George Dishman <geo...(a)briar.demon.co.uk> wrote: >> >On 15 Oct, 23:24, HW@....(Clueless Henri Wilson) wrote: >> George, your mistake is in assuming that the rays are always in phase when they >> meet. they are not. > >The signal emitted is of the form > > Ve = A * sin(w*t + phi) > >for both rays. Both take the same time to reach the >detector, say T. The signal received is therefore > > Vr = A * sin(w*t + phi - T) > >for both rays, they are in phase. No it doesn't work like that. You seem to think the source emits sine waves..... when it emits photon PARTICLES. >> >> Fringe movement and displacement change occurs only during an acceleration, >> >> when 'wavelength' in each path is NOT the same. >> >> >No, fringe displacement is proportional to the >> >speed-induced phase difference at the detector. >> >> That's what I said. > >You said ".. displacement change occurs .." when you >should have said ".. displacement occurs ..". Displacement occurs whenever there is a rotation speed. That is, when the path lengths are different. >> The is a phase difference at the detector.....determined by the difference in >> number of wavelengths in each path. > >No, look at Jerry's simulaton again. > >> >Jerry's code is correct. >> >> It might be...but it doesn't model a ring gyro. > >True, it models Sagnac. It doesn't model sagnac either. >> >> >Try to think that through Henry, I'm sure it will >> >> >give you some difficulty. >> >> >> I have already George. Much of what you say is basically correct except that >> >> you are completely overlooking the vital question of what happens during an >> >> acceleration. >> >> The answer is, "everything". >> >> >The fringes will vary in a complex way but there >> >is no memory in the system. Sagnac didn't switch >> >on the light bulb until the speed was stable so >> >what would have happened to fringes had he switched >> >on the bulb is moot, only the phase difference >> >while the bulb was on matters. >> >> George, the rays are not in phase when they reunite. >> You seem to think this should be the case just because the travel times are the >> same. That does not follow. > >It does Henry, see the maths above. that doesn't apply. >> Think again George. > >Look again at jerry's animation, look specifically >at the leading edge when the waves start and watch >it arrive at the detector. Notice that the other >wave arrives at the same time but more importantly >the radius of the two waves is the same and they >stay the same thereafter. Pause the display and look >back round the circumference until you reach the >source and note they are being emitted in phase >9.5 cycles earlier. Ballistic theory requires that >they be in phase, they hit the detector 9.5 cycles >after they were emitted. From the yellow dot, they >_move_ a distance greater than 9.5 wavelengths but >they do that in the time of 9.5 cycles because they >move at c+v while the wavelength is independent of >the speed. .....but that's not how it works. One one 'photon' (eg., cycle) is emitted at the emission point. I will soon have the correct animation running. It's not all that easy to program. >George Henri Wilson. ASTC,BSc,DSc(T) www.users.bigpond.com/hewn/index.htm
From: Androcles on 17 Oct 2007 18:09 "Dr. Henri Wilson" <HW@....> wrote in message news:ksvch3p330390s753krok4p0e51hr9k6un(a)4ax.com... : On Wed, 17 Oct 2007 00:47:49 GMT, "Androcles" <Engineer(a)hogwarts.physics> : wrote: : : > : >"Dr. Henri Wilson" <HW@....> wrote in message : >news:s6fah3hr1l27bkm48mtodblbhl79afkk5u(a)4ax.com... : >: On Mon, 15 Oct 2007 22:41:48 GMT, "Androcles" <Engineer(a)hogwarts.physics> : >: wrote: : >: : >: > : >: >"Dr. Henri Wilson" <HW@....> wrote in message : >: >news:u8p7h3l41okcp8vsnitaikbp10e04fipan(a)4ax.com... : >: : >: >: >>>You get the same wavelength by either method. : >: >: > : >: >: >Get it yet? : >: >: > : >: >: >"You get the same wavelength by either method." : >: >: > : >: >: >I am saying your claim is _correct_ so stop and : >: >: >_think_ before disagreeing! : >: >: : >: >: I'm basicaly disagreeing with him. : >: > : >: > : >: >That's good, Wilson, I want it on record that you disagreed with me. : >: > : >: >"There are about 13 waves in the blue and 6 in the red." --Wilson, 12 Oct : >: >2007. : >: >"the number of waves between the source and detector is : >: >the same in both paths and constant." -- Wilson, 15 Oct 2007. : >: : >: Both above statements are correct. : >: It is no fault of mine if you cannot get into your head that the : >'stationary : >: emission point' is NOT the same thing as the 'moving source'. : > : > : >It is no fault of mine if you cannot count. : > http://www.androcles01.pwp.blueyonder.co.uk/tickfairy.gif : >How many teeth on each wheel have I drawn? : > Is it : >A) 20 : >B) 21 : >C) 22 : >D) 23 : >E) 24 : >F) 25 : >G) 26 : >H) 27 : >I) 28 : >J) 29 : >K) 30 : >L) Other ......................... (specify) : : ..now count the number Wrong answer, Wombat, try again. How many teeth on each wheel have I drawn? Is it A) 20 B) 21 C) 22 D) 23 E) 24 F) 25 G) 26 H) 27 I) 28 J) 29 K) 30 L) Other ......................... (specify) To help your hopeless little mind I've the lock the wheels in phase. See if you can COUNT, pathetic cretin. http://www.androcles01.pwp.blueyonder.co.uk/tickfairy2.gif How many teeth on each wheel have I drawn?
From: Dr. Henri Wilson on 17 Oct 2007 19:03 On Wed, 17 Oct 2007 22:09:59 GMT, "Androcles" <Engineer(a)hogwarts.physics> wrote: > >"Dr. Henri Wilson" <HW@....> wrote in message >news:ksvch3p330390s753krok4p0e51hr9k6un(a)4ax.com... >: On Wed, 17 Oct 2007 00:47:49 GMT, "Androcles" <Engineer(a)hogwarts.physics> >: wrote: >: >: > >: >"Dr. Henri Wilson" <HW@....> wrote in message >: >news:s6fah3hr1l27bkm48mtodblbhl79afkk5u(a)4ax.com... >: >: On Mon, 15 Oct 2007 22:41:48 GMT, "Androcles" ><Engineer(a)hogwarts.physics> >: >: wrote: >: >: >: >: > >: >: >"Dr. Henri Wilson" <HW@....> wrote in message >: >: >news:u8p7h3l41okcp8vsnitaikbp10e04fipan(a)4ax.com... >: >: >: >: >: >>>You get the same wavelength by either method. >: >: >: > >: >: >: >Get it yet? >: >: >: > >: >: >: >"You get the same wavelength by either method." >: >: >: > >: >: >: >I am saying your claim is _correct_ so stop and >: >: >: >_think_ before disagreeing! >: >: >: >: >: >: I'm basicaly disagreeing with him. >: >: > >: >: > >: >: >That's good, Wilson, I want it on record that you disagreed with me. >: >: > >: >: >"There are about 13 waves in the blue and 6 in the red." --Wilson, 12 >Oct >: >: >2007. >: >: >"the number of waves between the source and detector is >: >: >the same in both paths and constant." -- Wilson, 15 Oct 2007. >: >: >: >: Both above statements are correct. >: >: It is no fault of mine if you cannot get into your head that the >: >'stationary >: >: emission point' is NOT the same thing as the 'moving source'. >: > >: > >: >It is no fault of mine if you cannot count. >: > http://www.androcles01.pwp.blueyonder.co.uk/tickfairy.gif >: >How many teeth on each wheel have I drawn? >: > Is it >: >A) 20 >: >B) 21 >: >C) 22 >: >D) 23 >: >E) 24 >: >F) 25 >: >G) 26 >: >H) 27 >: >I) 28 >: >J) 29 >: >K) 30 >: >L) Other ......................... (specify) >: >: ..now count the number > >Wrong answer, Wombat, try again. >How many teeth on each wheel have I drawn? > Is it >A) 20 >B) 21 >C) 22 >D) 23 >E) 24 >F) 25 >G) 26 >H) 27 >I) 28 >J) 29 >K) 30 >L) Other ......................... (specify) > >To help your hopeless little mind I've the lock the wheels in phase. >See if you can COUNT, pathetic cretin. > http://www.androcles01.pwp.blueyonder.co.uk/tickfairy2.gif >How many teeth on each wheel have I drawn? Mark a point on the rim to represent the emission point of a particular photon. How many teeth are in the two paths it follows before arriving at the detector? Henri Wilson. ASTC,BSc,DSc(T) www.users.bigpond.com/hewn/index.htm
From: Androcles on 17 Oct 2007 19:15
"Dr. Henri Wilson" <HW@....> wrote in message news:325dh39umst5fbn3nq4der743n73f6v5fr(a)4ax.com... : On Wed, 17 Oct 2007 22:09:59 GMT, "Androcles" <Engineer(a)hogwarts.physics> : wrote: : : > : >"Dr. Henri Wilson" <HW@....> wrote in message : >news:ksvch3p330390s753krok4p0e51hr9k6un(a)4ax.com... : >: On Wed, 17 Oct 2007 00:47:49 GMT, "Androcles" <Engineer(a)hogwarts.physics> : >: wrote: : >: : >: > : >: >"Dr. Henri Wilson" <HW@....> wrote in message : >: >news:s6fah3hr1l27bkm48mtodblbhl79afkk5u(a)4ax.com... : >: >: On Mon, 15 Oct 2007 22:41:48 GMT, "Androcles" : ><Engineer(a)hogwarts.physics> : >: >: wrote: : >: >: : >: >: > : >: >: >"Dr. Henri Wilson" <HW@....> wrote in message : >: >: >news:u8p7h3l41okcp8vsnitaikbp10e04fipan(a)4ax.com... : >: >: : >: >: >: >>>You get the same wavelength by either method. : >: >: >: > : >: >: >: >Get it yet? : >: >: >: > : >: >: >: >"You get the same wavelength by either method." : >: >: >: > : >: >: >: >I am saying your claim is _correct_ so stop and : >: >: >: >_think_ before disagreeing! : >: >: >: : >: >: >: I'm basicaly disagreeing with him. : >: >: > : >: >: > : >: >: >That's good, Wilson, I want it on record that you disagreed with me. : >: >: > : >: >: >"There are about 13 waves in the blue and 6 in the red." --Wilson, 12 : >Oct : >: >: >2007. : >: >: >"the number of waves between the source and detector is : >: >: >the same in both paths and constant." -- Wilson, 15 Oct 2007. : >: >: : >: >: Both above statements are correct. : >: >: It is no fault of mine if you cannot get into your head that the : >: >'stationary : >: >: emission point' is NOT the same thing as the 'moving source'. : >: > : >: > : >: >It is no fault of mine if you cannot count. : >: > http://www.androcles01.pwp.blueyonder.co.uk/tickfairy.gif : >: >How many teeth on each wheel have I drawn? : >: > Is it : >: >A) 20 : >: >B) 21 : >: >C) 22 : >: >D) 23 : >: >E) 24 : >: >F) 25 : >: >G) 26 : >: >H) 27 : >: >I) 28 : >: >J) 29 : >: >K) 30 : >: >L) Other ......................... (specify) : >: : >: ..now count the number : > : >Wrong answer, Wombat, try again. : >How many teeth on each wheel have I drawn? : > Is it : >A) 20 : >B) 21 : >C) 22 : >D) 23 : >E) 24 : >F) 25 : >G) 26 : >H) 27 : >I) 28 : >J) 29 : >K) 30 : >L) Other ......................... (specify) : > : >To help your hopeless little mind I've the lock the wheels in phase. : >See if you can COUNT, pathetic cretin. : > http://www.androcles01.pwp.blueyonder.co.uk/tickfairy2.gif : >How many teeth on each wheel have I drawn? : : Mark a point Wrong answer, Wilson. How many teeth on each wheel have I drawn? Is it A) 20 B) 21 C) 22 D) 23 E) 24 F) 25 G) 26 H) 27 I) 28 J) 29 K) 30 L) Other ......................... (specify) To help your hopeless little mind I've the lock the wheels in phase. See if you can COUNT, pathetic cretin. http://www.androcles01.pwp.blueyonder.co.uk/tickfairy2.gif How many teeth on each wheel have I drawn? |