Let's settle the argument When gravity has no strength mpc.
in [Relativity]
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From: BURT on 10 Jun 2010 22:03 I don't know what you are doing here. You sure are not addressing me. Do you do your own work? Or are you just repeating what you have read over and over? Mitch Raemsch
From: YBM on 10 Jun 2010 22:24 BURT a �crit : > I don't know what you are doing here. You sure are not addressing me. > > Do you do your own work? Or are you just repeating what you have read > over and over? "mpc755" is doing EXACTLY what you are doing here. Ok, he's using more words than you are, whatever both of you are MEANINGLESS. Completlye MEANINGLESS.
From: mpc755 on 10 Jun 2010 22:42 On Jun 10, 10:03 pm, BURT <macromi...(a)yahoo.com> wrote: > I don't know what you are doing here. You sure are not addressing me. > > Do you do your own work? Or are you just repeating what you have read > over and over? > > Mitch Raemsch There is still an outstanding question you have not answered. Double slit experiments have been performed with C-60 molecules. 'Interpretation of quantum mechanics by the double solution theory Louis de BROGLIE' http://www.ensmp.fr/aflb/AFLB-classiques/aflb124p001.pdf 'I called this relation, which determines the particle's motion in the wave, "the guidance formula". It may easily be generalized to the case of an external field acting on the particle.' 'The particle when in motion on its wave, thus has its vibration constantly in phase with that of the wave. This result may be interpreted by noticing that, in the present theory, the particle is defined as a very small region of the wave where the amplitude is very large, and it therefore seems quite natural that the internal motion rythm of the particle should always be the same as that of the wave at the point where the particle is located. A very important point must be underlined here. For this interpretation of the guidance to be acceptable, the dimensions of the minute singular region constituting the particle ought to be very small compared to the wavelength of the v wave.' The 'particle' occupies a very small region of its associated wave. The external field acting on the particle is the aether. A moving particle has an associated aether wave. http://en.wikipedia.org/wiki/De_Broglie%E2%80%93Bohm_theory "In de BroglieBohm theory, the wavefunction travels through both slits, but each particle has a well-defined trajectory and passes through exactly one of the slits." You said you agreed with Bohm. Bohm states the particle, in this case a C-60 molecule, has a well-defined trajectory and passes through exactly one of the slits. Do you agree with Bohm or don't you?
From: BURT on 10 Jun 2010 23:38 On Jun 10, 7:24 pm, YBM <ybm...(a)nooos.fr.invalid> wrote: > BURT a écrit : > > > I don't know what you are doing here. You sure are not addressing me. > > > Do you do your own work? Or are you just repeating what you have read > > over and over? > > "mpc755" is doing EXACTLY what you are doing here. > > Ok, he's using more words than you are, whatever both of you are > MEANINGLESS. > > Completlye MEANINGLESS. Did you know you are lying to yourself? By what meaning do you live by you hypocrite? You fight him not me now. Mitch Raemsch
From: BURT on 10 Jun 2010 23:40
On Jun 10, 7:42 pm, mpc755 <mpc...(a)gmail.com> wrote: > On Jun 10, 10:03 pm, BURT <macromi...(a)yahoo.com> wrote: > > > I don't know what you are doing here. You sure are not addressing me. > > > Do you do your own work? Or are you just repeating what you have read > > over and over? > > > Mitch Raemsch > > There is still an outstanding question you have not answered. > > Double slit experiments have been performed with C-60 molecules. > > 'Interpretation of quantum mechanics > by the double solution theory > Louis de BROGLIE'http://www.ensmp.fr/aflb/AFLB-classiques/aflb124p001.pdf > > 'I called this relation, which determines the particle's motion in the > wave, "the guidance formula". It may easily be generalized to the case > of an external field acting on the particle.' > > 'The particle when in motion on its wave, thus has its vibration > constantly in phase with that of the wave. This result may be > interpreted by noticing that, in the present theory, the particle is > defined as a very small region of the wave where the amplitude is very > large, and it therefore seems quite natural that the internal motion > rythm of the particle should always be the same as that of the wave at > the point where the particle is located. A very important point must > be underlined here. For this interpretation of the guidance to be > acceptable, the dimensions of the minute singular region constituting > the particle ought to be very small compared to the wavelength of the > v wave.' > > The 'particle' occupies a very small region of its associated wave. > The external field acting on the particle is the aether. > > A moving particle has an associated aether wave. > > http://en.wikipedia.org/wiki/De_Broglie%E2%80%93Bohm_theory > > "In de BroglieBohm theory, the wavefunction travels through both > slits, but each particle has a well-defined trajectory and passes > through exactly one of the slits." > > You said you agreed with Bohm. Bohm states the particle, in this case > a C-60 molecule, has a well-defined trajectory and passes through > exactly one of the slits. > > Do you agree with Bohm or don't you? Quantum mechanics isn't objective. But the push by the wave of the particle of energy I believe. This is called quantum vibration float in space. Mitch Raemsch |