The proof of mass vector.
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From: Phineas T Puddleduck on 11 Dec 2006 19:21 In article <1165882744.955562.213440(a)j72g2000cwa.googlegroups.com>, "yen, ka-in" <yenkain(a)yahoo.com.tw> wrote: > In three dimensional vector algebra, area HAS TO be a vector, > and we can divide an area vector of a rectangle by the length > vector of this rectangle. Area vectors can only be defined for flat surfaces. -- Just \int_0^\infty du it! -- Posted via a free Usenet account from http://www.teranews.com
From: Eric Gisse on 11 Dec 2006 22:05 yen, ka-in wrote: > In three dimensional vector algebra, area HAS TO be a vector, > and we can divide an area vector of a rectangle by the length > vector of this rectangle. Look who fails vector analysis again! [...]
From: Ka-In Yen on 12 Dec 2006 19:27 Phineas T Puddleduck wrote: > In article <1165882744.955562.213440(a)j72g2000cwa.googlegroups.com>, > "yen, ka-in" <yenkain(a)yahoo.com.tw> wrote: > > > In three dimensional vector algebra, area HAS TO be a vector, > > and we can divide an area vector of a rectangle by the length > > vector of this rectangle. > > Area vectors can only be defined for flat surfaces. Yes, and calculus can help you work on curvy surfaces.
From: Phineas T Puddleduck on 12 Dec 2006 19:42 In article <1165969633.567611.103040(a)j72g2000cwa.googlegroups.com>, "Ka-In Yen" <yenkain(a)yahoo.com.tw> wrote: > > Phineas T Puddleduck wrote: > > In article <1165882744.955562.213440(a)j72g2000cwa.googlegroups.com>, > > "yen, ka-in" <yenkain(a)yahoo.com.tw> wrote: > > > > > In three dimensional vector algebra, area HAS TO be a vector, > > > and we can divide an area vector of a rectangle by the length > > > vector of this rectangle. > > > > Area vectors can only be defined for flat surfaces. > > Yes, and calculus can help you work on curvy surfaces. So how are you going to define an area vector for a curved surface -- Just \int_0^\infty du it! -- Posted via a free Usenet account from http://www.teranews.com
From: Virgil on 12 Dec 2006 20:38
In article <phineaspuddleduck-0B341E.00423413122006(a)free.teranews.com>, Phineas T Puddleduck <phineaspuddleduck(a)googlemail.com> wrote: > In article <1165969633.567611.103040(a)j72g2000cwa.googlegroups.com>, > "Ka-In Yen" <yenkain(a)yahoo.com.tw> wrote: > > > > > Phineas T Puddleduck wrote: > > > In article <1165882744.955562.213440(a)j72g2000cwa.googlegroups.com>, > > > "yen, ka-in" <yenkain(a)yahoo.com.tw> wrote: > > > > > > > In three dimensional vector algebra, area HAS TO be a vector, > > > > and we can divide an area vector of a rectangle by the length > > > > vector of this rectangle. > > > > > > Area vectors can only be defined for flat surfaces. > > > > Yes, and calculus can help you work on curvy surfaces. > > So how are you going to define an area vector for a curved surface Using Clifford algebra? |