The proof of mass vector.
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From: Ka-In Yen on 28 Dec 2006 19:39 Sam Wormley wrote: > Ka-In Yen wrote: > > Pmb wrote: > >> "Phineas T Puddleduck" <phineaspuddleduck(a)googlemail.com> wrote in message > >> news:458fd74a$0$15523$88260bb3(a)free.teranews.com... > >>> On 2006-12-25 04:33:44 +0000, "yen, ka-in" <yenkain(a)yahoo.com.tw> said: > >>> > >>>> Thank you for your question. In 3D vector algebra, there are > >>>> four basic operations: addition, dot product, cross product, and > >>>> scalar multiplication. To get the area of the parallelogram generated > >>>> from vectors A and B, cross product has to be used: area=AXB; > >>>> so the area HAS TO be a vector. > >>> And the area is only defined for flat space. > >> I don't follow. Who was it that claimed that area was a vector???? That's > >> total nonsense. Taking the cross product of two vectors does yield another > >> vector. The *magnitude* of the vector being equal to the parallelagram > >> defined by the two vectors. > > > > Dear Pete, > > > > Thank for your comment. In 3D vector algebra, there are four > > basic operations: addition, dot product, cross product, and > > scalar multiplication. A parallelepiped is constructed from three > > vectors: A, B, and C. The volume of the parallelepiped is > > volume=A dot (B cross C). > >>From the above equation, we can conclude that area HAS > > TO be a vector. > > > > Volume = A.BxC = C.AxB = B.CxA > Area_1 = A.B = B.A Your second BALL. Could you write down your derivation step by step? Do you mean A.BxC=(A.B)xC? Please refer to triple product: http://mathworld.wolfram.com/ScalarTripleProduct.html > Area_2 = C.B = B.C > Area_3 = C.A = A.C
From: Sam Wormley on 28 Dec 2006 19:43 Ka-In Yen wrote: > Sam Wormley wrote: >> Ka-In Yen wrote: >>> Pmb wrote: >>>> "Phineas T Puddleduck" <phineaspuddleduck(a)googlemail.com> wrote in message >>>> news:458fd74a$0$15523$88260bb3(a)free.teranews.com... >>>>> On 2006-12-25 04:33:44 +0000, "yen, ka-in" <yenkain(a)yahoo.com.tw> said: >>>>> >>>>>> Thank you for your question. In 3D vector algebra, there are >>>>>> four basic operations: addition, dot product, cross product, and >>>>>> scalar multiplication. To get the area of the parallelogram generated >>>>>> from vectors A and B, cross product has to be used: area=AXB; >>>>>> so the area HAS TO be a vector. >>>>> And the area is only defined for flat space. >>>> I don't follow. Who was it that claimed that area was a vector???? That's >>>> total nonsense. Taking the cross product of two vectors does yield another >>>> vector. The *magnitude* of the vector being equal to the parallelagram >>>> defined by the two vectors. >>> Dear Pete, >>> >>> Thank for your comment. In 3D vector algebra, there are four >>> basic operations: addition, dot product, cross product, and >>> scalar multiplication. A parallelepiped is constructed from three >>> vectors: A, B, and C. The volume of the parallelepiped is >>> volume=A dot (B cross C). >>> >From the above equation, we can conclude that area HAS >>> TO be a vector. >>> >> Volume = A.BxC = C.AxB = B.CxA >> Area_1 = A.B = B.A > > Your second BALL. > > Could you write down your derivation step by step? > Do you mean A.BxC=(A.B)xC? > Please refer to triple product: > http://mathworld.wolfram.com/ScalarTripleProduct.html > >> Area_2 = C.B = B.C >> Area_3 = C.A = A.C > Strike three -- Yer Out!
From: Ka-In Yen on 29 Dec 2006 19:11 Sam Wormley wrote: > Ka-In Yen wrote: > > Sam Wormley wrote: > >> Ka-In Yen wrote: > >>> Pmb wrote: > >>>> "Phineas T Puddleduck" <phineaspuddleduck(a)googlemail.com> wrote in message > >>>> news:458fd74a$0$15523$88260bb3(a)free.teranews.com... > >>>>> On 2006-12-25 04:33:44 +0000, "yen, ka-in" <yenkain(a)yahoo.com.tw> said: > >>>>> > >>>>>> Thank you for your question. In 3D vector algebra, there are > >>>>>> four basic operations: addition, dot product, cross product, and > >>>>>> scalar multiplication. To get the area of the parallelogram generated > >>>>>> from vectors A and B, cross product has to be used: area=AXB; > >>>>>> so the area HAS TO be a vector. > >>>>> And the area is only defined for flat space. > >>>> I don't follow. Who was it that claimed that area was a vector???? That's > >>>> total nonsense. Taking the cross product of two vectors does yield another > >>>> vector. The *magnitude* of the vector being equal to the parallelagram > >>>> defined by the two vectors. > >>> Dear Pete, > >>> > >>> Thank for your comment. In 3D vector algebra, there are four > >>> basic operations: addition, dot product, cross product, and > >>> scalar multiplication. A parallelepiped is constructed from three > >>> vectors: A, B, and C. The volume of the parallelepiped is > >>> volume=A dot (B cross C). > >>> >From the above equation, we can conclude that area HAS > >>> TO be a vector. > >>> > >> Volume = A.BxC = C.AxB = B.CxA > >> Area_1 = A.B = B.A > > > > Your second BALL. > > > > Could you write down your derivation step by step? > > Do you mean A.BxC=(A.B)xC? > > Please refer to triple product: > > http://mathworld.wolfram.com/ScalarTripleProduct.html > > > >> Area_2 = C.B = B.C > >> Area_3 = C.A = A.C > > > > Strike three -- Yer Out! Do'nt dodge. I am waiting for your derivation. Could you write down your derivation step by step? Do you mean A.BxC=(A.B)xC?
From: Phineas T Puddleduck on 29 Dec 2006 19:12 On 2006-12-30 00:11:08 +0000, "Ka-In Yen" <yenkain(a)yahoo.com.tw> said: > Do'nt dodge. I am waiting for your derivation. > Could you write down your derivation step by step? > Do you mean A.BxC=(A.B)xC? What is the exact form of A (note: *not* dA) for an irregular shape on an irregularly curved surface? -- For me, it is far better to grasp the Universe as it really is than to persist in delusion, however satisfying and reassuring. Carl Sagan -- Posted via a free Usenet account from http://www.teranews.com
From: Ka-In Yen on 29 Dec 2006 19:22
Phineas T Puddleduck wrote: > On 2006-12-30 00:11:08 +0000, "Ka-In Yen" <yenkain(a)yahoo.com.tw> said: > > > Do'nt dodge. I am waiting for your derivation. > > Could you write down your derivation step by step? > > Do you mean A.BxC=(A.B)xC? > > What is the exact form of A (note: *not* dA) for an irregular shape on > an irregularly curved surface? Go ask your teacher, I will not give you free e-touring any more. |