The proof of mass vector.
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From: Phineas T Puddleduck on 12 Dec 2006 20:40 In article <virgil-880920.18384212122006(a)comcast.dca.giganews.com>, Virgil <virgil(a)comcast.net> wrote: > In article <phineaspuddleduck-0B341E.00423413122006(a)free.teranews.com>, > Phineas T Puddleduck <phineaspuddleduck(a)googlemail.com> wrote: > > > In article <1165969633.567611.103040(a)j72g2000cwa.googlegroups.com>, > > "Ka-In Yen" <yenkain(a)yahoo.com.tw> wrote: > > > > > > > > Phineas T Puddleduck wrote: > > > > In article <1165882744.955562.213440(a)j72g2000cwa.googlegroups.com>, > > > > "yen, ka-in" <yenkain(a)yahoo.com.tw> wrote: > > > > > > > > > In three dimensional vector algebra, area HAS TO be a vector, > > > > > and we can divide an area vector of a rectangle by the length > > > > > vector of this rectangle. > > > > > > > > Area vectors can only be defined for flat surfaces. > > > > > > Yes, and calculus can help you work on curvy surfaces. > > > > So how are you going to define an area vector for a curved surface > > Using Clifford algebra? Tell Ka-In... -- Just \int_0^\infty du it! -- Posted via a free Usenet account from http://www.teranews.com
From: Eric Gisse on 12 Dec 2006 21:29 Phineas T Puddleduck wrote: > In article <1165969633.567611.103040(a)j72g2000cwa.googlegroups.com>, > "Ka-In Yen" <yenkain(a)yahoo.com.tw> wrote: > > > > > Phineas T Puddleduck wrote: > > > In article <1165882744.955562.213440(a)j72g2000cwa.googlegroups.com>, > > > "yen, ka-in" <yenkain(a)yahoo.com.tw> wrote: > > > > > > > In three dimensional vector algebra, area HAS TO be a vector, > > > > and we can divide an area vector of a rectangle by the length > > > > vector of this rectangle. > > > > > > Area vectors can only be defined for flat surfaces. > > > > Yes, and calculus can help you work on curvy surfaces. > > So how are you going to define an area vector for a curved surface Here comes the fun part. > > -- > > Just \int_0^\infty du it! > > -- > Posted via a free Usenet account from http://www.teranews.com
From: crank_hunter on 14 Dec 2006 09:56 Eric Gisse wrote: > yen, ka-in wrote: > > In three dimensional vector algebra, area HAS TO be a vector, > > and we can divide an area vector of a rectangle by the length > > vector of this rectangle. > > Look who fails vector analysis again! > > [...] Eric Gisse is marked by Crank Alert: http://groups.google.gr/group/sci.physics.relativity/tree/browse_frm/thread/4841325a3c938f44/01b8793b2b1f235b?rnum=311&hl=en&_done=%2Fgroup%2Fsci.physics.relativity%2Fbrowse_frm%2Fthread%2F4841325a3c938f44%3Fscoring%3Dd%26hl%3Den%26&scoring=d#doc_01b8793b2b1f235b "F = ma, F = GmM/r^2. m*dr^2/dt^2 = GmM/r^2 r^2 * dr^2/dt^2 = GM The rest is left as an exercise. Do you know how to solve an ODE? I'll give you a hint: http://mathworld.wolfram.com/EulerDifferentialEquation.html " http://groups.google.gr/group/sci.physics.relativity/tree/browse_frm/thread/6656e57a32f8da73/8de1d639d237c151?rnum=91&hl=en&_done=%2Fgroup%2Fsci.physics.relativity%2Fbrowse_frm%2Fthread%2F6656e57a32f8da73%3Fscoring%3Dd%26hl%3Den%26&scoring=d#doc_18b28dea41093521 "A rocket fired from inside a train that is moving with constant velocity is an inertial frame - it doesn't accelerate, and is thus inertial. " Crank Alert is a free service by Crank Hunter
From: Phineas T Puddleduck on 14 Dec 2006 10:00 In article <1166108206.047191.60070(a)16g2000cwy.googlegroups.com>, crank_hunter(a)yahoo.com wrote: > > Eric Gisse is marked by Crank Alert: Cowardly spammer through anonymous proxy. -- Just \int_0^\infty du it! -- Posted via a free Usenet account from http://www.teranews.com
From: Randy Poe on 14 Dec 2006 10:50
yen, ka-in wrote: > In three dimensional vector algebra, area HAS TO be a vector, Writing it in caps doesn't make it so. Why does area have to be a vector? What makes you think scalars can't exist in 3-space? - Randy |