The proof of mass vector.
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From: Eric Gisse on 27 Dec 2006 20:00 yen, ka-in wrote: > Phineas T Puddleduck wrote: > > On 2006-12-28 00:02:32 +0000, "Ka-In Yen" <yenkain(a)yahoo.com.tw> said: > > > > >>> Dear Sam Wormley, > > >>> > > >>> Thank for your information. A strong pitching, but BALL. :( > > >>> The target is the A, not A' . So please aim to the A, and pitch > > >>> again. > > >>> > > >> > > >> Remember - three strikes and yer out! > > > > > > Three strikes and Einstein out! > > > Mathematically I prove that Einstein was ill-trained in 3D > > > vector algebra; STR was based on incomplete physical > > > mathematics. > > > > Mathematically you prove nothing > > > > In an arbitrarily curved manifold, what does the area vector represent? > > I.e for a surface that is corrugated like cardboard, what direction > > does the area vector of an irregularly drawn shape on the surface take > > and what does it represent? > > Please refer to area integral: > http://hyperphysics.phy-astr.gsu.edu/hbase/intare.html#c1 I think you first need to learn vector algebra before you move on to vector calculus.
From: Phineas T Puddleduck on 27 Dec 2006 20:03 On 2006-12-28 00:44:28 +0000, "yen, ka-in" <yenkain(a)yahoo.com.tw> said: > Please refer to area integral: > http://hyperphysics.phy-astr.gsu.edu/hbase/intare.html#c1 Great for dA, but what about A? A is a unique, single vector... -- For me, it is far better to grasp the Universe as it really is than to persist in delusion, however satisfying and reassuring. Carl Sagan -- Posted via a free Usenet account from http://www.teranews.com
From: Phineas T Puddleduck on 27 Dec 2006 20:04 On 2006-12-28 01:00:09 +0000, "Eric Gisse" <jowr.pi(a)gmail.com> said: >>> Mathematically you prove nothing >>> >>> In an arbitrarily curved manifold, what does the area vector represent? >>> I.e for a surface that is corrugated like cardboard, what direction >>> does the area vector of an irregularly drawn shape on the surface take >>> and what does it represent? >> >> Please refer to area integral: >> http://hyperphysics.phy-astr.gsu.edu/hbase/intare.html#c1 > > I think you first need to learn vector algebra before you move on to > vector calculus. Note he cannot answer the question... ;-) -- For me, it is far better to grasp the Universe as it really is than to persist in delusion, however satisfying and reassuring. Carl Sagan -- Posted via a free Usenet account from http://www.teranews.com
From: Sam Wormley on 27 Dec 2006 20:11 Ka-In Yen wrote: > Pmb wrote: >> "Phineas T Puddleduck" <phineaspuddleduck(a)googlemail.com> wrote in message >> news:458fd74a$0$15523$88260bb3(a)free.teranews.com... >>> On 2006-12-25 04:33:44 +0000, "yen, ka-in" <yenkain(a)yahoo.com.tw> said: >>> >>>> Thank you for your question. In 3D vector algebra, there are >>>> four basic operations: addition, dot product, cross product, and >>>> scalar multiplication. To get the area of the parallelogram generated >>>> from vectors A and B, cross product has to be used: area=AXB; >>>> so the area HAS TO be a vector. >>> And the area is only defined for flat space. >> I don't follow. Who was it that claimed that area was a vector???? That's >> total nonsense. Taking the cross product of two vectors does yield another >> vector. The *magnitude* of the vector being equal to the parallelagram >> defined by the two vectors. > > Dear Pete, > > Thank for your comment. In 3D vector algebra, there are four > basic operations: addition, dot product, cross product, and > scalar multiplication. A parallelepiped is constructed from three > vectors: A, B, and C. The volume of the parallelepiped is > volume=A dot (B cross C). >>From the above equation, we can conclude that area HAS > TO be a vector. > Volume = A.BxC = C.AxB = B.CxA Area_1 = A.B = B.A Area_2 = C.B = B.C Area_3 = C.A = A.C
From: Sam Wormley on 27 Dec 2006 20:34
yen, ka-in wrote: > > Please refer to area integral: > http://hyperphysics.phy-astr.gsu.edu/hbase/intare.html#c1 > Where dA is a vector "normal to the area" at a point on the surface. |