The proof of mass vector.
in [Math]
|
Prev: infinity ...
Next: The set of All sets
From: Phineas T Puddleduck on 25 Dec 2006 12:45 On 2006-12-25 15:01:45 +0000, "Pmb" <peter102560_nospam(a)comcast.net> said: >> On 2006-12-25 04:33:44 +0000, "yen, ka-in" <yenkain(a)yahoo.com.tw> said: >> >>> Thank you for your question. In 3D vector algebra, there are >>> four basic operations: addition, dot product, cross product, and >>> scalar multiplication. To get the area of the parallelogram generated >>> from vectors A and B, cross product has to be used: area=AXB; >>> so the area HAS TO be a vector. >> >> And the area is only defined for flat space. > > I don't follow. Who was it that claimed that area was a vector???? > That's total nonsense. Taking the cross product of two vectors does > yield another vector. The *magnitude* of the vector being equal to the > parallelagram defined by the two vectors. > > Regards > > Pete This is the guy who claims area is a vector... ;-) > yen, ka-in" <yenkain(a)yahoo.com.tw> said: -- For me, it is far better to grasp the Universe as it really is than to persist in delusion, however satisfying and reassuring. Carl Sagan -- Posted via a free Usenet account from http://www.teranews.com
From: Ka-In Yen on 26 Dec 2006 19:31 Sam Wormley wrote: > yen, ka-in wrote: > > Randy Poe wrote: > >> yen, ka-in wrote: > >>> In three dimensional vector algebra, area HAS TO be a vector, > >> Writing it in caps doesn't make it so. > >> > >> Why does area have to be a vector? > >> > >> What makes you think scalars can't exist in 3-space? > > > > Dear Randy, > > > > Thank you for your question. In 3D vector algebra, there are > > four basic operations: addition, dot product, cross product, and > > scalar multiplication. To get the area of the parallelogram generated > > from vectors A and B, cross product has to be used: area=AXB; > > so the area HAS TO be a vector. > > > > Area is not a vector quantity. > > Inner Product(Dot Product) > http://www.ies.co.jp/math/java/vector/naiseki_e/naiseki_e.html Dear Sam Wormley, Thank for your information. A strong pitching, but BALL. :( The target is the A, not A' . So please aim to the A, and pitch again.
From: Ka-In Yen on 26 Dec 2006 19:39 Pmb wrote: > "Phineas T Puddleduck" <phineaspuddleduck(a)googlemail.com> wrote in message > news:458fd74a$0$15523$88260bb3(a)free.teranews.com... > > On 2006-12-25 04:33:44 +0000, "yen, ka-in" <yenkain(a)yahoo.com.tw> said: > > > >> Thank you for your question. In 3D vector algebra, there are > >> four basic operations: addition, dot product, cross product, and > >> scalar multiplication. To get the area of the parallelogram generated > >> from vectors A and B, cross product has to be used: area=AXB; > >> so the area HAS TO be a vector. > > > > And the area is only defined for flat space. > > I don't follow. Who was it that claimed that area was a vector???? That's > total nonsense. Taking the cross product of two vectors does yield another > vector. The *magnitude* of the vector being equal to the parallelagram > defined by the two vectors. Dear Pete, Thank for your comment. In 3D vector algebra, there are four basic operations: addition, dot product, cross product, and scalar multiplication. A parallelepiped is constructed from three vectors: A, B, and C. The volume of the parallelepiped is volume=A dot (B cross C). >From the above equation, we can conclude that area HAS TO be a vector.
From: Ka-In Yen on 26 Dec 2006 19:44 Pmb wrote: > "Phineas T Puddleduck" <phineaspuddleduck(a)googlemail.com> wrote in message > news:458fd74a$0$15523$88260bb3(a)free.teranews.com... > > On 2006-12-25 04:33:44 +0000, "yen, ka-in" <yenkain(a)yahoo.com.tw> said: > > > >> Thank you for your question. In 3D vector algebra, there are > >> four basic operations: addition, dot product, cross product, and > >> scalar multiplication. To get the area of the parallelogram generated > >> from vectors A and B, cross product has to be used: area=AXB; > >> so the area HAS TO be a vector. > > > > And the area is only defined for flat space. > > I don't follow. Who was it that claimed that area was a vector???? That's > total nonsense. Taking the cross product of two vectors does yield another > vector. The *magnitude* of the vector being equal to the parallelagram > defined by the two vectors. Dear Pete, Thank for your comment. In 3D vector algebra, there are four basic operations: addition, dot product, cross product, and scalar multiplication. A parallelepiped is constructed from three vectors: A, B, and C. The volume of the parallelepiped is volume=A dot (B cross C). >From the above equation, we can conclude that area HAS TO be a vector.
From: Ka-In Yen on 26 Dec 2006 19:48
Pmb wrote: > "Phineas T Puddleduck" <phineaspuddleduck(a)googlemail.com> wrote in message > news:458fd74a$0$15523$88260bb3(a)free.teranews.com... > > On 2006-12-25 04:33:44 +0000, "yen, ka-in" <yenkain(a)yahoo.com.tw> said: > > > >> Thank you for your question. In 3D vector algebra, there are > >> four basic operations: addition, dot product, cross product, and > >> scalar multiplication. To get the area of the parallelogram generated > >> from vectors A and B, cross product has to be used: area=AXB; > >> so the area HAS TO be a vector. > > > > And the area is only defined for flat space. > > I don't follow. Who was it that claimed that area was a vector???? That's > total nonsense. Taking the cross product of two vectors does yield another > vector. The *magnitude* of the vector being equal to the parallelagram > defined by the two vectors. Dear Pete, Thank for your comment. In 3D vector algebra, there are four basic operations: addition, dot product, cross product, and scalar multiplication. A parallelepiped is constructed from three vectors: A, B, and C. The volume of the parallelepiped is volume=A dot (B cross C). >From the above equation, we can conclude that area HAS TO be a vector. |